How is the sum expressed in sigma notation? 127+19+13+1+3 Responses ∑i=15((13)i+3) sum from i equals 1 to 5 left parenthesis left parenthesis 1 third right parenthesis to the power of i plus 3 end exponent right parenthesis ∑i=15(3i−4) sum from i equals 1 to 5 of left parenthesis 3 to the power of i minus 4 end exponent right parenthesis ∑i=15(3−i−2) sum from i equals 1 to 5 left parenthesis 3 to the power of negative i minus 2 end exponent right parenthesis ∑i=15((13)i+2)