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A ball is thrown into the air with an upward velocity of 32 ft/s. Its height h in feet after t seconds is given by the function h = –16t2 + 32t + 6. a. In how many seconds does the ball reach its maximum height? Round to the nearest hundredth if necessary. b. What is the ball’s maximum height?

Respuesta :

if you graph it you can see what the max height is

but how do you show it 

well do you know what a derivative is?
h=-32t + 32 + 0

t= 1

then plug into h(1)= -16(1)^2 + 32(1)+ 6
max height is 22

if you dont, then i will have to solve another way

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