kellycm0101
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Darin skateboarded to the north at 4 m/s. In 5 seconds, he sped up to 7 m/s. What was his acceleration?

A. -0.6 m/s2 north
B. -1.66 m/s2 north
C. 0.6 m/s2 north
D. 1.66 m/s2 north

Respuesta :

Ishankahps
To solve this problem we can use following equation.

v =u + at

Where v is the final velocity (m/s), u is the initial velocity (m/s), a is the acceleration (m/s²) and t is the time taken (s).

v = 7 m/s
u = 4 m/s
a = ?
t = 5 s

By applying the equation, we can get
    7 m/s = 4 m/s + a x 5 s
    3 m/s = a x 5 s
          a = 0.6 m/s²

Hence, the acceleration is 0.6 m/s² towards north.

Answer is "C".

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