contestada

A 6.00-μf parallel-plate capacitor has charges of 40.0 μc on its plates. how much potential energy is stored in this capacitor?

Respuesta :

Thew energy stored in a capacitor of capacitance [tex] C [/tex] and voltage between the plates [tex] V [/tex] is

[tex] E=\frac{1}{2} CV^2=\frac{1}{2C} Q^2 [/tex].

Substituting numerical value

[tex] E=\frac{1}{2*6*10^{-6}} (40*10^{-6})^2\\
E=133.33\; \mu J [/tex]