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The rectangular boat shown below has base dimensions 10.0 cm × 8.0 cm. Each cube has a mass of 40 g, and the liquid in the tank has a density of 1.0 g/mL. How far has the boat sunk into the water?

Respuesta :

When boat is sunk into the liquid the net buoyancy on the boat is counterbalanced by weight of the boat

So here weight of the boat = Buoyancy force

let say boat is sunk by distance "h"

now we can say

[tex]F_b = \rho * V * g[/tex]

[tex]F_b = 1000*0.10 * 0.08 * h * 9.8[/tex]

now by above force balance equation we can write

[tex]m*g = F_b[/tex]

[tex]0.040 * 9.8 = 1000 * 0.10 * 0.08 * h * 9.8[/tex]

[tex]0.040 = 8h[/tex]

[tex]h = 5 * 10^{-3} m[/tex]

so boat will sunk by total 5 mm distance

Answer:

4.0

Explanation:

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