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A projectile is fired with a velocity of 22 m/s at an angle of 25°. What is the vertical component of the velocity?

Respuesta :

Answer:

Vertical component of velocity is 9.29 m/s

Explanation:

Given that,

Velocity of projection of a projectile, v = 22 m/s

It is fired at an angle of 22°

The horizontal component of velocity is v cosθ

The vertical component of velocity is v sinθ

So, vertical component is given by :

[tex]v_y=v\ sin(25)[/tex]

[tex]v_y=22\ m/s\times\ sin(25)[/tex]

[tex]v_y=9.29\ m/s[/tex]

Hence, the vertical component of the velocity is 9.29 m/s

Answer:

9.3 m/s

Explanation:

Just got it right :)