Respuesta :

YOU also better mark me BRAINLIEST if someone else answers!!!

1)

volume = 100 mL

density = 1.02 g / mL

mass = density x volume

  • = 1.02 x 100
  • = 102 g
  1. Cp = 4.03 J / oc g
  2. dT = 28.7 - 23.5 = 5.2 oC
  3. Q = m Cp dT
  4. Q = 102 x 4.03 x 5.2
  5. Q = 2138 J
  6. Q = 2.14 kJ

heat absorbed = 2.14 kJ

2)

  • We can calculate the moles of HC1 present in 50 ml 1m solution by using the formula, moles = volume of solution  in L*molarity
  • moles = 50/1000 = .05 , L*1 M = .05 Moles of HCL.
  • The same can be applied for calculation  of moles fo  Na OH of 50 ml, 1 M solution. (50 ml NaOH = .o5 L NaOH)
  • Then use the formula = volume of solution / 1000*moles.wt,
  • =1.825 gram.
  • moles=mass in grams /moles.wt= .05 moles of HCI
  • calculate moles of water from this reaction.
  • HC1+NaOH----->NACl+h20 (Balanced Equation)
  • .5+.5----> .5+.5
  • .05 moles of water
  • Delta H=q/n.
  • n=.05 to calculate the Delat H.

3) I don't understand it, sorry


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