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What is the equation of a line that has a slope of -5 and passes through the point (0, 2)? y = -5x y = -5x + 2 y = 2x - 5.

Respuesta :

tarhunbalthazar

y = -5x + 2 because the point given tells us the y-intercept, and the slope is already given to us, -5/1.

JeanaShupp

Answer: [tex]y=-5x+2[/tex]

Step-by-step explanation:

We know that the equation of a line that passing through (a,b) and has slope m is given by :-

[tex](y-b)=m(x-a)[/tex]

Given : Slope: m = -5   ; Point : (a,b) = (0, 2)

Then, the equation of a line that has a slope of -5 and passes through the point (0, 2)will be :-

[tex](y-2)=-5(x-0)\\\\\Rightarrow\ y-2=-5x\\\\\Rightarrow\ y=-5x+2[/tex]

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