Respuesta :

gmany

[tex]f(x)=\dfrac{x}{4}-3=\dfrac{1}{4}x-3\\\\g(x)=4x^2+2x-4\\\\(f+g)(x)=f(x)+g(x)=\dfrac{1}{4}x-3+4x^2+2x-4\\\\=4x^2+\left(\dfrac{1}{4}x+2x\right)+(-3-4)=4x^2+2\dfrac{1}{4}x-7[/tex]

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