The answer is D 50 units because using the distance formula x1 minus x2 is 50. That squared is 2500. y1 minus y2 is 0 and zeros squared is 0. 2500 plus 0 is then 2500 and the distance between the two points is the square root of 2500 which is 50 units.
[tex] d = \sqrt{{(x1 - x2)}^{2} + {(y1 - y2)}^{2} } [/tex]
