[tex]\bf \begin{array}{ccll} \${data-answer}amp;lbs\\ \cline{1-2} 1.48&1\\ x&2\frac{4}{5} \end{array}\implies \cfrac{1.48}{x}=\cfrac{1}{2\frac{4}{5}}\implies \cfrac{1.48}{x}=\cfrac{\frac{1}{1}}{\frac{14}{5}}\implies \cfrac{1.48}{x}=\cfrac{1}{1}\cdot \cfrac{5}{14} \\\\\\ \cfrac{1.48}{x}=\cfrac{5}{14}\implies 20.72=5x\implies \cfrac{20.72}{5}=x\implies 4.144=x[/tex]
