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What is an equation in slope-intercept form of the line that passes through the points (−2, −2) and (1, 7)? A.y = 4x + 3 B.y − 7 = 3(x − 1) C.y = 3x + 4 Dy + 2 = 3(x + 2)

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wegnerkolmp2741o

Answer:

C.y = 3x + 4

Step-by-step explanation:

We have two points, so we can find the slope

m = (y2-y1)/ (x2-x1)

   = (7--2)/ (1--2)

   = (7+2)/(1+2)

    = 9/3

    =3

The slope is 3

We can find the point slope form of the line

y-y1 = m(x-x1)

y-7 = 3(x-1)

Distribute

y-7 =3x-3

Add 7 to each side

y-7+7 = 3x-3+7

y = 3x+4

This is in slope intercept form (y=mx+b)

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