Answer:
0.037
Step-by-step explanation:
If the hitter makes an out 72% of the time, then the probabilty that he makes hit in 1 at-bat is [tex]p=0.72[/tex] and the probabilty that he doesn't make hit in 1 at-bat is [tex]q=1-p=1-0.72=0.28.[/tex]
The probability that the hitter makes 10 outs in 10 consecutive at-bats, assuming at-bats are independent events is
[tex]P=p^{10}=(0.72)^{10}\approx 0.037.[/tex]
