Respuesta :

LammettHash

The probabilities of all possible outcomes in a distribution must sum to 1.

[tex]\dfrac5{12}+\dfrac16+\dfrac13+x=1\implies x=\dfrac1{12}[/tex]

Answer:

1/12 C

Step-by-step explanation:

5/12

1/6=2/12

1/3=4/12

5/12-3=2/12

2/12+2=4/12

4/12-3= 1/12

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