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A solution was prepared by mixing 50.0 g
MgSO4
and 1000.0 mL water at 25.0°C. The density of the water at this temperature is 0.997 g/mL. What is the percent mass of
MgSO4
in this solution? (Round your answer to the nearest hundredth.)

Respuesta :

superman1987

Answer:

4.78 %.

Explanation:

mass percent is the ratio of the mass of the solute to the mass of the solution multiplied by 100.

mass % = (mass of solute/mass of solution) x 100.

mass of MgSO₄ = 50.0 g,

mass of water = d.V = (0.997 g/mL)(1000.0 mL) = 997.0 g.

mass of the solution = mass of water + mass of MgSO₄ = 997.0 g + 50.0 g = 1047.0 g.

∴ mass % = (mass of solute/mass of solution) x 100 = (50.0 g/1047.0 g) x 100 = 4.776 % ≅ 4.78 %.

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