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Find three consecutive even integers such that the sum is of the least and the middle is 48 more than the greatest

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MathPhys

Answer:

50, 52, and 54

Step-by-step explanation:

The three even integers are x, x+2, and x+4.  The sum of the least two is 48 more than the greatest:

x + x+2 = x+4 + 48

2x + 2 = x + 52

x = 50

So the three integers are 50, 52, and 54.

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