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Four (4.0) liters of helium gas are stored at 125 atm pressure. If the temperature and number of particles do not change, what will be the new volume when the pressure is decreased to 50 atm? Show your work.

Please answer ASAP!!

Respuesta :

znk

Answer:

10 L

Explanation:

The only variables are pressure and volume, so we can use Boyle's Law:

p1V1 = p2V2

Data:

p1 = 125 atm; V1  = 4.0 L  

p2 =  50 atm; V2 = ?

Calculation:

125 × 4.0 = 50V2

       500 = 50 V2

        V2 = 500/50 = 10 L

The new volume will be 10 L.

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