Answer: 1. [tex]2NaHCO_3\rightarrow Na_2CO_3+CO_2+H_2O[/tex]
2. 100.8 grams
Explanation:
According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.
Balanced equation for the decomposition of the compound sodium hydrogen carbonate is:
[tex]2NaHCO_3\rightarrow Na_2CO_3+CO_2+H_2O[/tex]
According to avogadro's law, 1 mole of every substance weighs equal to its molecular mass and contains avogadro's number [tex]6.023\times 10^{23}[/tex] of particles.
moles of [tex]CO_2=\frac{\text {given mass}}{\text {molar mass}}=\frac{27.0g}{44g/mol}=0.6moles[/tex]
According to stoichiometry:
1 mole of [tex]CO_2[/tex] is produced from 2 moles of [tex]NaHCO_3[/tex]
Thus 0.6 moles of [tex]CO_2[/tex] is produced from =[tex]\frac{2}{1}\times 0.6=1.2[/tex] moles of [tex]NaHCO_3[/tex]
Mass of [tex]NaHCO_3=moles\times {\text {Molar mass}}=1.2\times 84=100.8g[/tex]
Thus the mass of [tex]NaHCO_3[/tex] required to produce 27.0 g of [tex]CO_2[/tex] is 100.78 grams.