According to the​ label, a can of soup holds an average of 307 ​grams, with a standard deviation of 4.1 grams. Assuming a normal​ distribution, what is the probability that a can will be sold that holds more than 308 ​grams?

Respuesta :

Answer: 0.4052

Step-by-step explanation:

Given : Mean : [tex]\mu=\text{307 ​grams}[/tex]

Standard deviation : [tex]\sigma = \text{4.1 grams}[/tex]

The formula for z -score :

[tex]z=\dfrac{x-\mu}{\sigma}[/tex]

For x=308 ,

[tex]z=\dfrac{308-307}{4.1}=0.24390\approx0.24[/tex]

The p-value = [tex]P(z>0.24)=1-P(z<0.24)[/tex]

[tex]=1-0.5948348= 0.4051652\approx0.4052[/tex]

Hence, the probability that a can will be sold that holds more than 308 ​grams =0.4052.