Explanation:
y = y₀ + v₀ᵧ t + ½ gt²
where y is the final height,
y₀ is the initial height,
v₀ᵧ is the initial vertical velocity,
g is the acceleration due to gravity,
and t is time.
0 m = 0 m + (5 sin 55º m/s) t + ½ (-9.8 m/s²) t²
0 = 4.10 t − 4.9 t²
0 = t (4.10 − 4.9 t)
t = 0, t = 0.84
The bobcat lands after 0.84 seconds.
