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Given P(A) 0.169, P(B) 0.041, and P(C) 0.172, and that events A, B, and C are mutually exclusive, what is the P(A or B or C)? Answer in decimal form. Round to 3 decimal places as needed Your Answer: Answer

Respuesta :

Answer:

The value of P(A or B or C) is 0.382.

Step-by-step explanation:

Given,

P(A) = 0.169,

P(B) = 0.041,

P(C) = 0.172

Since, if events A, B and C are mutually events ( in which no  element is common ),

Then, P(A∪B∪C) = P(A) + P(B) + P(C)

Or  P(A or B or C) = P(A) + P(B) + P(C),

By substituting the values,

P(A or B or C) = 0.169 +  0.041 +  0.172 = 0.382