Answer:
0.3659
Explanation:
The power (p) is given as:
P = AeσT⁴
where,
A =Area
e = transmittivity
σ = Stefan-boltzmann constant
T = Temperature
since both the bulbs radiate same power
P₁ = P₂
Where, 1 denotes the bulb 1
2 denotes the bulb 2
thus,
A₁e₁σT₁⁴ = A₂e₂σT₂⁴
Now e₁=e₂
⇒A₁T₁⁴ = A₂T₂⁴
or
[tex]\frac{A_1}{A_2} =\frac{T_{2}^{4}}{T_{1}^{4}}[/tex]
substituting the values in the above question we get
[tex]\frac{A_1}{A_2} =\frac{2100_{2}^{4}}{2700_{1}^{4}}[/tex]
or
[tex]\frac{A_1}{A_2} }[/tex]=0.3659
