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In a quasi-static isobaric expansion, the gas does 26.4 J of work. The initial pressure and volume of the gas is 0.9 atm and 19 L. If the internal energy of the gas increases by 80 J in the expansion, how much heat does the gas absorb?

Respuesta :

Answer:

Q = 106.4 J

Explanation:

Given that

Process is isobaric.

Work done by gas (W)= 26. 4 J

Volume of the gas at initial condition  = 0.9 L

Volume of the gas at final condition  = 19 L

Increase in the internal energy of gas = 80 J

we know that from first law of thermodynamics

 Q = ΔU + W

Here Q is the heat absorb by gas

ΔU change in internal energy of gas

W is the work done by gas

So now by putting the values

Q = ΔU + W

Q = 80 + 26.4

Q = 106.4 J

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