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An unwary football player collides with a padded goalpost while running at a velocity of 7.10 m/s and comes to a full stop after compressing the padding and his body 0.360 m. (a) What is his deceleration in m/s2? (Enter the magnitude.)

Respuesta :

Answer:

football player decceleration is 70.01 m/s^2

Explanation:

given data:

x = 0.360

initial velocity vi = 7.10m/s

final velocity vf = 0 m/s

we know that acceleration is given as a

[tex]a =\frac{ vf^2 -vi^2}{2x}[/tex]

putting all value to get the desired value of acceleration:

[tex]a = \frac{ -(7.10)^2}{2*.360}[/tex]

a = - 70.01 m/s^2

negative sign indicate deceleration

football player decceleration is 70.01 m/s^2

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