What mass error (in mg, round to the nearest tenth) would occur in the weighing of 450 mg of a drug if the uncalibrated balance created a 15 % error in all measurements?

Respuesta :

Answer: 67.5

Step-by-step explanation:

Given: The mass of drug =  450 mg

The mass percent error = 15%

Which can be written as 0.15.

We use the formula :-

[tex]\text{Error}=\text{Previous value }\times\text{Percent error}[/tex]

Similarly, [tex]\text{Mass Error}=\text{Mass of drug }\times\text{Mass percent error}[/tex]

[tex]\Rightarrow\ \text{Mass Error}=450\times0.15=67.5\ mg[/tex]

Hence, the mass error would be  67.5 mg.