Consider a runner traveling with an initial velocity of 1.9 m/s in the positive direction accelerates at a constant rate of 1.2 m/s2 for a time of 3 seconds. What is his velocity at the end of this time?

Respuesta :

Answer: 5.5 m/s

Explanation:

As we are told the runner  accelerates at a constant rate, we can use the following equation:

[tex]V_{f}=V_{o} + at[/tex]

Where:

[tex]V_{f}[/tex] is the runner's final velocity

[tex]V_{o}=1.9 m/s[/tex] is the runner's initial velocity

[tex]a=1.2 m/s^{2}[/tex] is the runner's constant acceleration

[tex]t=3 s[/tex] is the time it takes the runner to reach the final velocity

[tex]V_{f}=1.9 m/s +(1.2 m/s^{2})(3 s)[/tex]

Finally:

[tex]V_{f}=5.5 m/s[/tex]