Explanation:
It is known that the specific heat capacity of Liver [tex](C_{p})[/tex] is 3.59 kJ [tex]kg^{-1}.K^{-1}[/tex]
It is given that :
Initial temperature of Liver = Body temperature = [tex]37^{o}C[/tex] = 310 K
Final temperature of Liver = 180 K
Relation between heat energy, mass, and change in temperature is as follows.
Q = [tex]m \times C_{p} \times \Delta T[/tex]
Now, putting the given values into the above formula as follows.
Q = [tex]m \times C_{p} \times \Delta T[/tex]
Q = [tex]1.5 kg \times 3.59 kJ/kg.K \times (310 - 180) K[/tex]
= 700.05 kJ
Therefore, we can conclude that amount of heat which must be removed from the liver is 700.05 kJ.
