Answer:
Initial velocity = 10 m/s
θ = 60°
This is the case of projectile motion
So the horizontal component of velocity 10 m/s = 10 cosθ
u = 10 cosθ
u = 10 cos 60°
u=5 m/s
x= 5 m
So in the horizontal direction
x = u .t
5 = 5 .t
t = 1 sec The vertical component of velocity 10 m/s = 10 sinθ
Vo= 10 sinθ
Vo= 10 sin 60°
Vo = 8.66 m/s
[tex]V^2=V_o^2+2gh[/tex]
[tex]0=V_o^2-2gh[/tex]
[tex]0=8.66^2-2\times 10\times h[/tex]
h=3.75 m
So height of robot = 3.75 - 0.75 m
height of robot =3 m
