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A bike accelerates uniformly from rest to a speed of 8.20 m/s over a distance of 45.6 m. Determine the
acceleration of the bike.

Respuesta :

MathPhys

Answer:

0.737 m/s²

Explanation:

Given:

v₀ = 0 m/s

v = 8.20 m/s

Δx = 45.6 m

Find: a

v² = v₀² + 2aΔx

(8.20 m/s)² = (0 m/s)² + 2a (45.6 m)

a = 0.737 m/s²

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