Answer:
A linearized model would be the best in this case, since R \simeq 1 .
Step-by-step explanation:
Since, R-value or the correlation coefficient is 0.977 or very close to 1, so
linearized model will be best suitable as least square regression model.
Since,
when R = 1
the points will accurately fall over a straight line having equation of the form
ax + by + c = 0 where a, b, c are fixed but otherwise arbitrary constants.
