Answer:14.14 cm
Explanation:
Given
Spring Compression [tex]x=12 cm[/tex]
Potential energy Stored in spring[tex]=72 J[/tex]
Suppose k is the spring constant of spring
Potential Energy of spring is given by [tex]=\frac{kx^2}{2}[/tex]
[tex]\frac{k(0.12)^2}{2}=72[/tex]
[tex]k(0.12)^2=144[/tex]
[tex]k=10,000 N/m[/tex]
[tex]k=10 kN/m[/tex]
for 100 J energy
[tex]\frac{k(x_0)^2}{2}=100[/tex]
[tex]10\times 10^3\cdot (x_0)^2=200[/tex]
[tex](x_0)^2=2\times 10^{-2}[/tex]
[tex]x_0=0.1414[/tex]
[tex]x_0=14.14 cm[/tex]
