Answer:
a=0
∑Fx = 0
Explanation:
Known data
m =1.7 kg : jeep's mass
θ = 12° :angle of the slope with respect to the horizontal direction
g = 9.8 m/s² : acceleration due to gravity
Newton's second law:
∑F = m*a Formula (1)
∑F : algebraic sum of the forces in Newton (N)
m : mass s (kg)
a : acceleration (m/s²)
We define the x-axis in the direction parallel to the movement of the block on the ramp and the y-axis in the direction perpendicular to it.
Calculated of the W
W= m*g
W= 1.7 kg* 9.8 m/s² = 16.66 N
x-y weight components
Wx= Wsin θ= 16.66*sin 12° = 3.45 N
Wy= Wcos θ =16.66*cos 12° = 16.3 N
a) Because the toy jeep lowers the ramp at a constant speed, then, its acceleration is equal to zero.
a=0
b)We apply the formula (1) to calculated ΣFx
∑Fx = m*a , a=0
∑Fx = 0
