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The products obtained by adding 1 mole of HBr to 2,4-hexadiene areA. 4-bromo-2-hexene and 5-bromo-2-hexene.B. 3-bromo-2-hexene and 4-bromo-2-hexene.C. 4-bromo-2-hexene and 2-bromo-4-hexene.D. 2-bromo-3-hexene and 3-bromo-2-hexene.E. 2-bromo-3-hexene and 4-bromo-2-hexene.

Respuesta :

Answer:

4-bromohex-2-ene (1,2 addition product)

2-bromohex-3-ene (1,4 addition product)

The structures of the products formed are shown in the figure.

Explanation:

On addition of HBr on 2,4-hexadiene there is possibility of both 1-2 and 1-4 addition.

The product will be according to markovnikov's rule.

The hydrogen will go to carbon bearing more number of hydrogens and bromine on the carbon bearing less number of hydrogens.

The structures of the products formed are shown in the figure.

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