Answer:
W = 0.3045 N
Explanation:
given,
mass of the object = 0.6
density of gold = 19.3 x 10³ kg/m³
density of water = 1000 Kg/m³
buoyant force = ?
Volume of the crown=
density = mass/volume
[tex]V = \dfrac{m}{\rho}[/tex]
[tex]V = \dfrac{0.6}{19.3\times 10^{3}}[/tex]
V = 3.108 x 10⁻⁵ m³
W = ρ V g
W = 1000 x 3.108 x 10⁻⁵ x 9.8
W = 0.3045 N
Buoyant force acting on the crown is equal to W = 0.3045 N
