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Calculate the volume in liters of a 0.00231M copper(II) fluoride solution that contains 175.g of copper(II) fluoride CuF2. Be sure your answer has the correct number of significant digits.

Respuesta :

Answer:

Volume = 746 L

Explanation:

Given that:- Mass of copper(II) fluoride = 175 g

Molar mass of copper(II) fluoride = 101.543 g/mol

The formula for the calculation of moles is shown below:

[tex]moles = \frac{Mass\ taken}{Molar\ mass}[/tex]

Thus,

[tex]Moles= \frac{175\ g}{101.543\ g/mol}[/tex]

[tex]Moles_{copper(II)\ fluoride}= 1.7234\ mol[/tex]

Also,

Considering:

[tex]Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}[/tex]

So,,

[tex]Volume =\frac{Moles\ of\ solute}{Molarity}[/tex]

Given, Molarity = 0.00231 M

So,

[tex]Volume =\frac{1.7234}{0.00231}\ L[/tex]

Volume = 746 L

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