Answer:
ω = 401.2 rad/sec
Explanation:
we know that in a circular motion
[tex]\omega= \omega_0+\alpha t[/tex]
ω= final angular velocity
ω0= initial angular velocity
α= angular aceleration
t= time
Given ω0= 0, [tex]\alpha= 118 rad/sec^2[/tex] and t=3.4 sec
to find final angular velocity that is ω
[tex]\omega= 0+118\times3.4[/tex]
⇒ω = 401.2 rad/sec
