Answer:
Length will be 0.491 nm
Explanation:
We have given wavelength of the photon [tex]\lambda =800nm=800\times 10^{-9}m[/tex]
Plank's constant [tex]h=6.6\times 10^{-34}J-s[/tex]
We know that energy of the photon is given by
[tex]E=\frac{hc}{\lambda }=\frac{6.6\times 10^{-34}\times 3\times 10^8}{800\times \times 10^{-9}}=2.475\times 10^{-19}J[/tex]
We know that energy of photon is also given by
[tex]E=\frac{n^2h^2}{8mL^2}=\frac{h^2}{8mL^2}[/tex]
[tex]2.475\times 10^{-19}=\frac{(6.6\times 10^{-34})^2}{8\times 9.1\times 10^{-31}\times L^2}[/tex]
[tex]L=0.491\times 10^{-9}m[/tex]
