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Consider a cross between a man with an X-linked recessive disorder and a woman that's a carrier for the disorder. Approximately what percent of their children are predicted to express the disorder?

Respuesta :

Answer:

50%

Explanation:

Let's assume that the X linked allele "a" gives the disorder. Therefore, the genotype of the affected man would be X^aY while the genotype of the carrier woman would be X^aX. A cross between X^aY man and X^aX woman would produce progeny in following phenotype ratio: 1 affected daughter: 1 affected son: 1 normal but carrier daughter: 1 normal son.

Therefore, there are 50% chances that their children can express the disorder.  

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