Answer:
[tex]\large\boxed{12d^{-22}=\dfrac{12}{d^{22}}}[/tex]
Step-by-step explanation:
[tex](-3d^{-8})(-4d^{-14})=\bigg((-3)(-4)\bigg)\bigg((d^{-8})(d^{-14})\bigg)\\\\\text{use}\ a^n\cdot a^m=a^{n+m}\\\\=12d^{-8+(-14)}=12d^{-22}[/tex]
[tex]\text{You can use}\ a^{-n}=\dfrac{1}{a^n}\\\\12d^{-22}=12\cdot\dfrac{1}{d^{22}}=\dfrac{12}{d^{22}}[/tex]
Answer:
12 / d^22.
Step-by-step explanation:
-3d^-8(-4d^-14)
= (-3*-4) d^(-8+-14)
= 12d^-22
= 12 /d^22.