Answer:
[tex]r_{1} = -6, r_{2} = -4[/tex]
Step-by-step explanation:
[tex]r_{1}[/tex] and [tex]r_{2}[/tex] are the eingenvalues of the equation, that is
the values of r when
[tex]r^{2} + 10r + 24 = 0[/tex]
Using r = (dy/dt).
They are
[tex]r = -6, r = -4[/tex]
r2 is larger than r1, so
[tex]r_{1} = -6, r_{2} = -4[/tex]