cbut2717 cbut2717

07-01-2020
Physics

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A block of mass 5 kg is descending with a constant velocity on an inclined plane at 30°. What is the value of the frictional force?

Respuesta :

Chelboy Chelboy

14-01-2020

Answer:28.9N

Explanation:

F=UR R=mg R=5×10 R=50N

U=tan© U=Tan30 U=1/√(3)

F=UR F=1/√(3) ×50

F=28.9N

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