A 1kg block of ice at 0o C falls into alake whose
water is also at 0o C, and 0.01 kg of the icemelts. What
was the minimum altitude from which the icefell?

Respuesta :

Answer:

340.01019 m

Explanation:

m =  Mass of ice = 1 kg

[tex]L_f[/tex] = Latent heat of fusion = [tex]333.55\times 10^3\ J/kg[/tex]

g = Acceleration due to gravity = 9.81 m/s²

M = Mass of water = 0.01 kg

The potential energy will balance the heat released

[tex]mgh=ML_f\\\Rightarrow h=\dfrac{ML_f}{mg}\\\Rightarrow h=\dfrac{0.01\times 333.55\times 10^3}{1\times 9.81}\\\Rightarrow h=340.01019\ m[/tex]

The minimum altitude is 340.01019 m