If oxygen were collected over water at 293 K and the
totalpressure of the wet gas were 670 mmHg, what would be the
partialpressure of the oxygen?

Respuesta :

Answer:

652 mmHg

Explanation:

Given data

  • Total pressure (P): 670 mmHg
  • Temperature (T): 293 K
  • Vapor pressure of water at 293 K (Pwater): 17.54 mmHg

When oxygen is collected over water, the total pressure is the sum of the partial pressures of oxygen and water vapor at the given temperature.

P = Poxygen + Pwater

Poxygen = P - Pwater

Poxygen = 670 mmHg - 17.54 mmHg

Poxygen = 652 mmHg