After 6 seconds, the car will surpass the cyclist.
The speed of the cyclist = 6 m/s.
Let after time t sec, the car will overtake the cyclist.
So, distance covered by the cyclist in t sec = 6t m
Initial velocity of the car is 0 m/s, because the car is just starting.
Acceleration of the car =[tex]2 m/s^2[/tex].
Final velocity of the car =6 m/s.
So to cover the distance 6t, the time required by the car = [tex]\frac{1}{2} \times a \times t^2 = \frac{1}{2} \times 2 \times t^2[/tex]
[tex]6t = \frac{1}{2} \times 2 \times t^2\\6t = t^2[/tex]
t =6 sec
So, after 6 seconds, the car will surpass the cycle.
