Answer
given,
constant net force = 75 N
distance = 0.60 m
mass = 0.20 Kg
a) by work energy theorem work done is equal to change in kinetic energy.
initial speed = 0 m/s
[tex]W = KE_f - KE_i[/tex]
[tex]KE_f - 0 = F .s[/tex]
[tex]KE_f = 75 x 0.6[/tex]
[tex]KE_f =45\ J[/tex]
b) We know.
[tex]KE_f =\dfrac{1}{2}mv^2[/tex]
[tex]45=\dfrac{1}{2}\times 0.20 \times v^2[/tex]
v² = 450
v = 21.21 m/s
the final speed of the object is equal to v = 21.21 m/s
