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What is the pressure at the bottom of a tank 1-m deep? Take the density of water to be 1000-kg/m^3, and gravitational acceleration to be 9.8-m/s^2. Enter your answer in N/m^2.

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To solve this problem we will use the concepts related to hydrostatic pressure. Which determines the pressure of a body at a given depth of a liquid.

Mathematically this can be described as

[tex]P= \rho gh[/tex]

Here

[tex]\rho[/tex] = Density

g = Gravity

h = Height (Depth)

If we replace the values given in the equation we will have to

[tex]P = 1000 (9.8)(1)[/tex]

[tex]P = 9800 Pa[/tex]

Therefore the pressure at the bottom will be 9.8kPa

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