amarislewis101972 amarislewis101972
  • 06-02-2020
  • Advanced Placement (AP)
contestada

The length of a rectangle is 3 less than twice the width. If the area of the rectangle is 50 square inches, choose the equation that could be used to solve for the dimensions.

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kudzordzifrancis
kudzordzifrancis kudzordzifrancis
  • 12-02-2020

Answer:

[tex]w(2w-3)=50[/tex]

Explanation:

Let the length of the rectangle be [tex]w[/tex] units.

We were given that the length is 3 less than twice the width.

This implies that: [tex]l=2w-3[/tex]

We have that the area of this rectangle is 50  square inches.

Recall that area of rectangle is given by:

[tex]A=lw[/tex]

[tex]\implies w(2w-3)=50[/tex]

Therefore the required equation is [tex]w(2w-3)=50[/tex]

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