Find the length of a rectangle given that the perimeter is 110 cm and the length is 1cm more than twice the width. Do not include units in your answer.

Respuesta :

The length of rectangle is 37 cm

Solution:

Given that,

Given is a rectangle

The length is 1cm more than twice the width

Let "w" be the width

Then,

length = 1 + 2w

Perimeter = 110 cm

The perimeter of rectangle is given as:

perimeter = 2(length + width)

Substitute the above values,

[tex]110 = 2(1 + 2w + w)\\\\110 = 2(1 + 3w)\\\\110 = 2 + 6w\\\\6w = 110 - 2\\\\6w = 108\\\\w = \frac{108}{6} = 18[/tex]

Therefore,

Length = 1 + 2w = 1 + 2(18) = 1 + 36 = 37

Thus length of rectangle is 37 cm