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Suppose a moving object has a kinetic energy of 100 J. What will the object's kinetic
energy be if it’s speed is doubled

Respuesta :

Answer:

400J

Explanation:

K. E = 1/2mv^2

If the speed is doubled, then it becomes :

K. E(2)= 1/2(m2v)^2

K. E(2) = 1/2m4v^2

K. E(2)=m2v^2

K. E(2)/K. E = (1/2mv^2)/(m2v^2)

K. E(2)/K. E =1/4

Therefore, K. E(2) = 4K.E

When k. E=100j

K. E(2)=4 *100 =400J

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