The line described in Assessment Problem 1.7 is 845 mi in length. The line contains four conductors, each weighing 2526 lb per 1000 ft. How many kilograms of conductor are in the line

Respuesta :

The question relates to a problem which description is missing, but I can answer it assuming all the data is present.

Answer:

[tex]m=20,461,723\ Kg[/tex]

Explanation:

Proportions

We know the line is 845 miles long. Let's convert it to feet

[tex]845 * 5280 =4,461,600 \ ft[/tex]

The weight per ft of the 4 conductors is

[tex]WPF=4*2526\ lb/1000\ ft=10104\ lb/1000\ ft=10.104\ lb/ft[/tex]

Since we have 4,461,600 ft of conductor, the total weight is

[tex]W=10.104\ lb/ft\times 4,461,600 \ ft=45,080,006.4\ lb[/tex]

Note: The unit 'lb' is understood as lb-f in this context, since it's an unit of weight, that is a force.

Converting to Newton

[tex]W=45,080,006.4\ lbf * 4.4482 = 200,524,884\ Nw[/tex]

Since W=m.g, we find the mass in kilograms by dividing by 9.8

[tex]m=200,524,884\ Nw/9.8=20,461,723\ Kg[/tex]

[tex]\boxed{m=20,461,723\ Kg}[/tex]